1.8*10^(-5)=x^2/0.1-x

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Solution for 1.8*10^(-5)=x^2/0.1-x equation: 


x in (-oo:+oo)

1.8*10^-5 = (x^2)/0.1-x // - (x^2)/0.1-x

x-((x^2)/0.1)+1.8*10^-5 = 0

x-10*x^2+1.8*10^-5 = 0

x-10*x^2+0.000018 = 0

DELTA = 1^2-(-10*0.000018*4)

DELTA = 1.00072

DELTA > 0

x = (1.00072^(1/2)-1)/(-10*2) or x = (-1.00072^(1/2)-1)/(-10*2)

x = (1.00072^(1/2)-1)/(-20) or x = (1.00072^(1/2)+1)/20

x in { (1.00072^(1/2)-1)/(-20), (1.00072^(1/2)+1)/20 }

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